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IIT Kharagpur

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Halfwave Rectifier Experiment



Introduction

Rectifiers:
Almost all electronic circuits require a dc source of power. For portable low power systems batteries may be used. More frequently, however, electronic equipment is energized by a power supply, a piece of equipment which converts the alter- nating waveform from the power lines into an essentially direct voltage.


Objective

To study the characteristics of halfwave rectifier with and without filter and to calculate the following parameters.

  • Ripple factor
  • Rectification efficiency


Theory

A device, such as the semiconductor diode, which is capable of converting a sinusoidal input waveform (whose average value is zero) into a unidirectional (though not constant) waveform, with a nonzero average component, is called a rectifier. The basic circuit for half-wave rectification is shown below.
 

Halfwave circuit

  In a rectifier circuit the input is a sinusiodal wave
 
\( v_i = V_m sin(wt) \)

  has a peak value V m which is very large compared with the cutin voltage \( V_T \) of the diode, we assume in the following discussion that \( V_\gamma = 0 \), (The condition \( V_I \neq 0 \) is treated. With the diode idealized to be a resistance \( R_f \) in the ON state and an open circuit in the OFF state, the current \( i \) in the diode or load \( R_L \) is given in
 
\( i = I_m sin(α) \qquad \quad if \quad 0 ≤ \alpha ≤ \pi \)
\( i =0 \qquad \qquad \qquad if \quad π ≤ \alpha ≤ 2\pi \)

  where \(\alpha = \omega t \) and
 
\( I_m =\frac{V_m}{R_f+R_L} \)

  Note that the output current is unidirectional. We now calculate this nonzero value of the average current. Sinusoidal voltage \( v_i \) Diode and Load Voltage \(i\)
  The voltage \( v_i \) is in figure and
 
Input plot

  the rectified diode voltage is in figure below
 
Output plot
.
  The input \( v_i \) and the rectified output \( v_o \) togeter in figure below
 
Input plot

  For a half wave rectifier,
 
\( V_{rms} = \frac{V_m}{2} \)
  \( V_{dc} = \frac{V_m}{\pi} \)

  where \(V_{rms} = \) rms value of input,
\( V_{dc} = \) Average value of input and
\( V_m = \) peak value of output.
 
  Ripple factor
 
\( r = \frac{V_{r,rms}}{V_{dc}} \)

  where \( V_{r,rms} \) is the rms value of the ac component. Since
 
\( {V_{rms}}^2 = {V_{r,rms}}^2+{V_{dc}}^2 \)

 
\( r =\sqrt{ (\frac{V_{rms}}{V_{dc}})^2-1}=1.21 \)

 


Pre-Quiz


Simulation

HaWa

    Instructions

  1. Observe the circuit diagram of the halfwave rectifier
  2. Click on the Power Button.
  3. Select the Amplitide(A) of the input sine wave signal(Vi).
  4. Select the frequency of the signal(f) for the input signal(Vi).
  5. Select the "Channel 1" to observe the input signal on graph
  6. Select the "Channel 2" to observe the rectified output signal on graph
  7. Select the "Dual" to observe the input signal and rectified output signal on graph
  8. Change the values of A, f to observe the variation in the input and output signals.
  9. Hover on the graph to observe the value of the Vi and Vo at that instatnt of time T.
  10. Save the graph if you are done with your experiment.
  11. Note:
    • Ideal diode is considered
    • Make sure always Input Signal Amplitude>0 v
    • Make sure always Input Signal Frequency>0 Hz
    • Load resistance \( R=1k \Omega \)
    • To change the values just scroll by hovering on it.

Power
Function Generator Controls

Vi = V

f = Hz
Oscilloscope Controls
Channel 1

Vc1 = V/div

Time = (ms)/div
Position

PX =

PY =
Channel 2

Vc2 = V/div

Time = (ms)/div
Position

PX =

PY =
 

Post-Quiz


Feedback


 

 

References


    Books


  • M. Halkias. Integrated Electronics. McGraw-Hill electrical and electronic engineering series. Tata McGraw-Hill Publishing Company, 2001.

  • NPTEL Lectures


  • Link 1

  • Link 2